Question icon
Grade 12Magical Mathematics[Interesting Approach]

Pls anyone solve this.Fast i need answer im unable to solve it

Question image for Pls anyone solve this.Fast i need answer im unabl
Profile image of sailokeshreddy
8 Years agoGrade 12
Answers icon

1 Answer

Profile image of Shashank Singh
8 Years ago
let the sides of an equilateral triangle be ‘a’
now using using geometry
we get the radius of circumcircle = R=a/v3
and radius of incircle = r= a/2v3
area of cicumcircle = pi*a^2/3
area of incircle = pi*a^2/12
the required probability = (area of circumcircle – area of incircle)/area of circumcircle
P(E)= (pi*a^2/3-pi*a^2/12)/pi*a^2/3
on solving we get P(E)=3/4= lambda1/lambda2
so, lambda1+lambda2= 7.......... [ans]